im trying to figure out how to write a gd class that will display a string in any font type i input.

Question

here is the class i have so far

<?php

class txt2img {

var $image;
var $headertype;
var $forecolor;
var $fontsize;
var $fontangle;
var $font;
var $string;


//font size
function fontsize($fontsize) {
    return $this->fontsize;
}

//forecolor
function forecolor($forecolor) {
    return this->imagecolorallocate($this->img(),$this->forecolor);
}

//image file
function img($image) {
    return imagecreatefrompng($this->img);
}





function display($string,$font) {

//display all errors
ini_set("display_errors", "1");
error_reporting(E_ALL);

header('content-type: image/png');
$fcolor = $this->forecolor();



imagettftext($this->img(),$this->fontsize(),0,0,$this->forecolor(),$this->font,$this->string);

imagejpg($this->img());
imagedestroy($this->img());

}


}

?>

anyone have any idea? either its late or i dont know, for some reason i feel blank when writing this one.

i want to be able to write the attribs first like

$gd = new gd; $gd->fontsize('12'); ..etc

then the actual output would be written like this

$gd->display('this is my string','myfont.ttf');

Answer 1

I think this line is not good

imagettftext($this->img(),$this->fontsize(),0,0,$this->forecolor(),$this->font,$this->string);

because you set nulls whit $this->fontsize() and etc.

it shuld be

imagettftext($this->imgage,$this->fontsize,0,0,$this->forecolor,$this->font,$this->string)

I this this helps :)

Answer 2

1. Get an IDE with SyntaxHighlighting
2. Learn PHP5 OOP Basics
3. Read the error messages

You have a wild mix of $this->img, $this->image, $this->img() and $image there ...