tags:

views:

675

answers:

3

Hey guys,

$value = $simpleXmlDoc->SomeNode->InnerNode;

actually assigns a simplexml object to $value instead of the actual value of InnerNode.

If I do:

$value = $simpleXmlDoc->SomeNode->InnerNode . "\n";

I get the value. Anyway of getting the actual value without the clumsy looking . "\n"?

+5  A: 

Cast as whatever type you want (and makes sense...). By concatenating, you're implicitly casting to string, so

$value = (string) $xml->someNode->innerNode;
Greg
A: 

What about using a typecast, like something like that :

$value = (string)$simpleXmlDoc->SomeNode->InnerNode;

See : type-juggling

Or you can probably use strval(), intval() and all that -- just probably slower, because of the function call.

Pascal MARTIN
A: 

Either cast it to a string, or use it in a string context:

$value = (string) $simpleXmlDoc->SomeNode->InnerNode;
// OR
echo $simpleXmlDoc->SomeNode->InnerNode;

See the SimpleXML reference functions guide

PatrikAkerstrand