Is this the DRYest way to do it in ruby?
<% for item in @items %>
<%= n = n + 1 rescue n = 1 %>
<% end %>
which initializes "n" to '1" and increments it as the loop progresses (and prints it out) since this is in one my app's views
views:
251answers:
2
+9
A:
You can use a ternary operator:
<% for item in @items %>
<%= n = n ? n+1 : 1 %>
<% end %>
But, depending on what you're trying to do, I'm guessing an each_with_index would be more appropriate
<% @items.each_with_index do |item, n| %>
<%= n %>
<% end %>
zaius
2009-07-19 19:31:53
Ah nice, I guess the second option is what I was looking for.
Zepplock
2009-07-19 19:45:36
Also is there a way to assign an initial value to "n"?
Zepplock
2009-07-19 19:48:07
Assign an initial value and then increment by 1 each time? The index isn't a counter - it's an index. If you want to increase it by a fixed offset, just add it when you print: <%= n + 5 %>
zaius
2009-07-19 21:15:08
Ah, I assume you mean that you're doing something [i]else[/i] with it in the loop, not shown in your example?
glenn mcdonald
2009-07-20 20:08:46