how can I get the segments off the uri

Question

Hello,

My question and the thing that goes wrong

is when I have two segments

example: www.xxx.nl/products/id

and I have this in the htaccess

RewriteEngine On
RewriteCond %{REQUEST_FILENAME} !-d
RewriteCond %{REQUEST_FILENAME} !-f
RewriteRule ^(.*)$ index.php?url=$1 [QSA,L]

is there a solution, or is this caust by the host

thanks in advance , Richard

Answer 1

The requested URI path and query is in $_SERVER['REQUEST_URI']. You can get the segments with this:

$_SERVER['REQUEST_URI_PATH'] = preg_replace('/\?.*/', '', $_SERVER['REQUEST_URI']);
$segments = explode('/', ltrim('/', $_SERVER['REQUEST_URI_PATH']));

Answer 2

You can use the parse_url function to parse any url and seperate it into relevant parts (assuming it's a valid url).

Answer 3

The url passed to index.php will never include the hostname, port, or query string. (Source: mod_rewrite docs).

Since the rest of the url is separated by forward slashes, you could use explode to turn it into an array.

$uri_segments = explode('/', $_GET['url']);

Note: What the array actually contains depends on where the RewriteRule occurs. If it's in an .htaccess file or <Directory> block, parts of the matched block will be missing (anything before the current directory in the url).