As the title says , i need to find 2 specific words in a sentence. But they can be in any order and any casing. How do i go about doing this using regex.
E.g. This is a very long sentence used as a test
From that sentence i need to extract the words test and long in any order i.e. test can be first or long can be first.
UPDATE: What i did not mention the first part is it needs to be case insensitive as well
without knowing what language
/test.*long/
or
/long.*test/
or
/test/ && /long/
I don't think that you can do it with a single regex. You'll need to d a logical AND of two - one searching for each word.
Use a capturing group if you want to extract the matches: (test)|(long) Then depending on the language in use you can refer to the matched group using $1 and $2, for example.
Try this:
/(?i)(?:test.*long|long.*test)/
That will match either test and then long, or long and then test. It will ignore case differences.
I assume (always dangerous) that you want to find whole words, so "test" would match but "testy" would not. Thus the pattern must search for word boundaries, so I use the "\b" word boundary pattern.
/(?i)(\btest\b.*\blong\b|\blong\b.*\btest\b)/