I'm new to sed, and need to grab just the filename from the output of find
. I need to have find output the whole path for another part of my script, but I want to just print the filename without the path. I also need to match starting from the beginning of the line, not from the end. In english, I want to match, the first group of characters ending with ".txt" not containing a "/". Here's my attempt that doesn't work:
ryan@fizz:~$ find /home/ryan/Desktop/test/ -type f -name \*.txt
/home/ryan/Desktop/test/two.txt
/home/ryan/Desktop/test/one.txt
ryan@fizz:~$ find /home/ryan/Desktop/test/ -type f -name \*.txt | sed s:^.*/[^*.txt]::g
esktop/test/two.txt
ne.txt
Here's the output I want:
two.txt
one.txt
Ok, so the solutions offered answered my original question, but I guess I asked it wrong. I don't want to kill the rest of the line past the file suffix i'm searching for. So, to be more clear, if the following:
bash$ new_mp3s=\`find mp3Dir -type f -name \*.mp3\` && cp -rfv $new_mp3s dest
`/mp3Dir/one.mp3' -> `/dest/one.mp3'
`/mp3Dir/two.mp3' -> `/dest/two.mp3'
What I want is:
bash$ new_mp3s=\`find mp3Dir -type f -name \*.mp3\` && cp -rfv $new_mp3s dest | sed ???
`one.mp3' -> `/dest'
`two.mp3' -> `/dest'
Sorry for the confusion. My original question just covered the first part of what I'm trying to do.
2nd edit: here's what I've come up with:
DEST=/tmp && cp -rfv `find /mp3Dir -type f -name \*.mp3` $DEST | sed -e 's:[^\`].*/::' -e "s:$: -> $DEST:"
This isn't quite what I want though. Instead of setting the destination directory as a shell variable, I would like to change the first sed
operation so it only changes the cp
output before the "->" on each line, so that I still have the 2nd part of the cp
output to operate on with another '-e'.
3rd edit: I haven't figured this out using only sed regex's yet, but the following does the job using Perl:
cp -rfv `find /mp3Dir -type f -name \*.mp3` /tmp | perl -pe "s:.*/(.*.mp3).*\`(.*/).*.mp3\'$:\$1 -> \$2:"
I'd like to do it in sed though.