How to get a reference to the module something is implemented in from within that implementation?

Question

Say I have the following code:

 from foo.bar import Foo
 from foo.foo import Bar

 __all__ = ["Foo", "Bar"]

 def iterate_over_all():
     ...

How can I implement code in the function iterate_over_all() that can dynamically obtain references to whatever is referenced in __all__ the module where the function is implemented? IE: in iterate_over_all() I want to work with foo.bar.Foo and foo.foo.Bar.

Answer 1

eval is one way. e.g. eval("Foo") would give you Foo. However you can also just put Foo and Bar directly in your list e.g. __all__ = [Foo, Bar]

It would depend on where the contents of __all__ is coming from in your actual program.

Answer 2

You can easily index with the strings from __all__ into the module's __dict__:

__dict__["Foo"] == foo.bar.Foo  # -> True

Answer 3

Would this do?

def iterate_over_all():
    for name in __all__:
        value = globals()[name]
        yield value # or do whatever with it