Given this text
"Foo(Bar)"
I'd like to extract "Bar" using a regex.
Help!
+4
A:
/.*\((.*)\)/
The first .* will match anything before the parenthetical, the second .* (within a capture) will match anything inside the parenthetical and return it for you.
(I assumed that the quotes in your example text were not actually part of the string you're wanting to match.)
Amber
2009-08-05 09:26:39
I Find this to be a bit OTT, it depends on what the OP wants, but if he just wants what he said then this is not necessary.
Salgar
2009-08-05 09:30:45
When reference is made to "Foo" and "Bar", the OP usually wants a generic solution, not how to look for "Bar".
Philippe Leybaert
2009-08-05 09:32:49
I realise that, but Dav's answer will suffice and is more readable to a larger proportion of the general programming population who are not regular expression experts.
Salgar
2009-08-05 09:34:49
+1
A:
Just search for "Bar".
For example in Groovy:
if("Foo(Bar)" =~ /Bar/) {
println "match"
}
Will print 'match'
Gregory Mostizky
2009-08-05 09:31:02
I think the assumption was that Foo and Bar were placeholder text that could vary.
Amber
2009-08-05 09:32:08
Personally, I think this is the best answer to the question as stated - match "Bar" within the string "Foo(Bar)" with a regex.
Dominic Rodger
2009-08-05 09:45:47
+1
A:
Should be enough:
\(.*\)
In Java the code would be:
String foo = "Foo(Bar)";
Pattern pattern = Pattern.compile("\(.*\)");
Matcher matcher = pattern.matcher(foo);
while (matcher.find()) {
int beginIndex=matcher.start();
int endIndex=matcher.end();
return foo.substring(beginIndex, endIndex);
ungarida
2009-08-05 09:45:27
A:
You are omitting quite a bit of information: no platform or language used, no indications about the types of text you receive (i.e. is "Foo" static or can it change? Is "Bar" static? etc.).
Picking Ruby and assuming that "Foo" is stable, you can do this:
$ ruby -e 'p "Foo(Bar)"[/Foo\(([^)]*)\)/, 1]'
"Bar"
$
Robert Klemme
2009-08-05 09:45:32