I have a user model and a cd model connected through a join table 'cds_users'. I'm trying to return a hash of users plus each cd they have in common with the original user.
@user.users_with_similar_cds(1,4,5)
# => {:bob => [4], :tim => [1,5]}
Is there a better/faster way of doing this without looping so much? Maybe a more direct way?
def users_with_similar_cds(*args)
similar_users = {}
Cd.find(:all, :conditions => ["cds.id IN (?)", args]).each do |cd|
cd.users.find(:all, :conditions => ["users.id != ?", self.id]).each do |user|
if similar_users[user.name]
similar_users[user.name] << cd.id
else
similar_users[user.name] = [cd.id]
end
end
end
similar_users
end
[addition]
Taking the join model idea, I could do something like this. I'll call the model 'joined'.
def users_with_similar_cds(*args)
similar_users = {}
Joined.find(:all, :conditions => ["user_id != ? AND cd_id IN (?)", self.id, args]).each do |joined|
if similar_users[joined.user_id]
similar_users[joined.user_id] << cd_id
else
similar_users[joined.user_id] = [cd_id]
end
end
similar_users
end
Would this be the fastest way on large data sets?