Quick Regex question

Question

Can anybody guide me in the right direction...

I have some folder strucktures that I want to check for a trailing / slash, some of the folders don't have a trailing / and if it does not have a trailing / I need to add one

If I use this regex it works but it replace the last character of the folder name

    Folder/name/test
    folder/name/test1/
    folder/name/test2/

replace(/.$/ig,"/");

This regex replaces Folder/name/tes[t]/ but will take out the t and replace it with /

Hope this makes sense...

Answer 1

I would avoid a regular expressions in this case and do something easier like:

$path = rtrim($path, '/').'/';

EDIT:

Woops, assumed it was php...

Answer 2

replace(/(.)$/ig,"\1/");

or better

replace(/([^\\])$/ig,"\1/");

if \1 isn't a backreference in your language, then you'll have to figure that out, or tell us teh language.

Answer 3

Without knowing the language it's difficult to post a correct answer and you can't use the code provided in a cut-and-paste fashion. Anyway I might go for this regex:

replace(/(.)\/*$/,"\1/");

This will append the trailing / only if it's not there yet.

Answer 4

Try something like this:

replace(/[^/]$/ig, "$0/")

Answer 5

The regex you made basically means this: take any character that is the last one in the string and replace it with /. What you need to do is to group the last character and then insert it again in the replacement, like this:

replace(/([^\/])$/ig,"$1/");

For more information see http://www.regular-expressions.info/brackets.html

Answer 6

I'm not sure which language this is for but this is how you would do it in Perl:

#! /local/bin/perl

my @data = <data>;
while (<DATA>)
{
    s#[^/]\n#/\n#m;
    print;
}

__DATA__
/foo/bar/
/baz/jazz
/baz/jazz

This then prints out the following:

/foo/bar/
/baz/jaz/
/baz/jazz/

The key to the regex is the "[^/]\n" This basically matches anything at the end next to to the newline. With your nomenclature, I would assume the syntax would be the following:

replace(/[^\/]\n/ig,"/");

Or if there is no newline use this:

replace(/[^\/]$/ig,"/");

I hope that helps.