use Request.Form command not Request.QueryString command with jquery

Question

I have simple registration form. Once all information entered, user click submit button and all information sent to default.cs.asp?Process=Add2Member. Everything works. Now, I am trying to implement it into ajax Jquery so that user will stay on same page. I looked at sample codes to do this. I am confused at one point. As I understand, with ajax, I will need to grab data as QueryString but I dont want that. How can I grab it as Request.Form again.

    $("[name='signup']").click(function() { 
            $.ajax({
                type: "GET",
    url: "default.cs.asp", 
    success: function(output) { 
                $("#SIGNUPFORM").html(output); 
    //$("#SIGNUPFORM").html(output).append("Üyeliğiniz başarıyla gerçekleşti. Lütfen emailinizi kontrol edin."); 
             },
    error: function(output) {
     $(".SIGNUPFORM").html(output);
    }
    //success: function(msg, textStatus){
    //alert( "Server Response: " + msg );
    //}
            });

edit: I made a mistake with type: field. Its GET, not POST.

Answer 1

First of all, you have two success methods, and you can only have one. Second, you need to post your data like data:{firstName:firstname',lastName:'lastname'}, etc. Since your request is a post you should be able to use request.forms again. I assume you're using an http handler?

Answer 2

Make the 'type' field 'POST'