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2436

answers:

4

I want to iterate over a treeMap, and for all 'key's which have a particular value, I want them to be added to a new TreeMap. How can i do this? Code samples would be prefered.

+2  A: 
    //create TreeMap instance
    TreeMap treeMap = new TreeMap();

    //add key value pairs to TreeMap
    treeMap.put("1","One");
    treeMap.put("2","Two");
    treeMap.put("3","Three");

    /*
      get Collection of values contained in TreeMap using
      Collection values()        
    */
    Collection c = treeMap.values();

    //obtain an Iterator for Collection
    Iterator itr = c.iterator();

    //iterate through TreeMap values iterator
    while(itr.hasNext())
      System.out.println(itr.next());

or:

   for (Map.Entry<K,V> entry : treeMap.entrySet() {
        V value = entry.getValue();
        K key = entry.getKey()
   }

or:

   // Use iterator to display the keys and associated values
   System.out.println("Map Values Before: ");
   Set keys = map.keySet();
   for (Iterator i = keys.iterator(); i.hasNext();) {
     Integer key = (Integer) i.next();
     String value = (String) map.get(key);
     System.out.println(key + " = " + value);
   }
karim79
+4  A: 

Assuming type TreeMap<String,Integer> :

for(Map.Entry<String,Integer> entry : treeMap.entrySet()) {
  String key = entry.getKey();
  Integer value = entry.getValue();

  System.out.println(key + " => " + value);
}

(key and Value types can be any class of course)

Zed
FYI, EntrySet is the preferred way to iterate through any Map since EntrySets are by specification reflective and always represent the state of data in the Map even if the Map underneath would change.
Esko
Preferred by who?
Zed
+7  A: 

Just like over any other map

serg
A: 

Using Google Collections, assuming K is your key type:

Maps.filterKeys(treeMap, new Predicate<K>() {
  @Override
  public boolean apply(K key) {
    return false; //return true here if you need the entry to be in your new map
  }});

You can use filterEntries instead if you need the value as well.

Jorn