How to use String#split() in Ruby?

Question

String is `ex="test1, test2, test3, test4, test5"

when I use

ex.split(",").first

it returns

"test1"

Now I want to get the remaining items, i.e. `"test2, test3, test4, test5". If I use

ex.split(",").last

it returns only

"test5"

how to get the remaining items skipping first one?

Answer 1

Try this:

first, *rest = ex.split(/, /)

Now first will be the first value, rest will be the rest of the array.

Answer 2

Since you've got an array, what you really want is Array#slice, not split.

rest = ex.slice(1 .. -1)
# or
rest = ex[1 .. -1]

Answer 3

You probably mistyped a few things. From what I gather, you start with a string such as:

string = "test1, test2, test3, test4, test5"

Then you want to split it to keep only the significant substrings:

array = string.split(/, /)

And in the end you only need all the elements excluding the first one:

# We extract and remove the first element from array
first_element = array.shift

# Now array contains the expected result, you can check it with
puts array.inspect

Did that answer your question ?

Answer 4

ex="test1,test2,test3,test4,test5"
all_but_first=ex.split(/,/)[1..-1]

Answer 5

ex.split(',', 2).last

The 2 says: split into 2 pieces, not more.

normally split will cut the value into as many pieces as it can, using a second value you can limit how many pieces you will get. Using "ex.split(',', 2)" will give you["test1", "test2, test3, test4, test5"] as an array, instead of ["test1", "test2", "test3", "test4", "test5"]

Answer 6

if u want to use them as an array u already knew, else u can use every one of them as a different parameter ... try this :

parameter1,parameter2,parameter3,parameter4,parameter5 = ex.split(",")