Why does this work:
List<?> list = new LinkedList<Integer>();
while this gives a type dismatch error:
List<List<?>> list = new LinkedList<List<Integer>>();
Why is this? Ist there a way around this, without using raw types?
Why does this work:
List<?> list = new LinkedList<Integer>();
while this gives a type dismatch error:
List<List<?>> list = new LinkedList<List<Integer>>();
Why is this? Ist there a way around this, without using raw types?
Try
List<? extends List<?>> list = new LinkedList<List<Integer>>();
Note: you should be aware that when you use a collection like List you will only be able to use it in "read only" mode (except for adding null values).
The way around this is
List<List<?>> list = new LinkedList<List<?>>();
You've not really lost anything there, either - your specification of Integer wasn't going to be helpful anywhere, since list
defined the inner Lists as using ?
To actually answer your question:
In the first case, "list" holds a list of one particular, unspecified type - in this case, Integer.
In the second case, "list" holds a list of lists, but each of the sublists may be of any particular type, but the following would be perfectly fine (note the types of the two lists being added):
List<List<?>> list = new LinkedList<List<?>>();
list.add(new LinkedList<Integer>());
list.add(new LinkedList<Double>());
It's very similar to the reason why you can't do
List<Object> listO = new List<Number>();
There are operations that would be perfectly valid on your list of lists of ? that would be illegal on the list of lists of Integers.
In order to do what you want (have a list of lists, where all the sublists are unique to a particular type), I think Zed's answer is about as close as you'll get.