How can I drop all indexes in a SQL database with one command?

Question

So, how can I drop all indexes in a SQL database with one command? I have this command that will get me all the 20 or so drop statements, but how can I run all of those drop statements from this "result set"?

select * from vw_drop_idnex;

Another variation that gives me the same list is:

SELECT  'DROP INDEX ' + ix.Name + ' ON ' + OBJECT_NAME(ID)  AS QUERYLIST
FROM  sysindexes ix
WHERE   ix.Name IS NOT null and ix.Name like '%pre_%'

I tried to do "exec(select cmd from vw_drop_idnex)" and it didn't work. I am looking for something that works like a for loop and runs the queries one by one.

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With Rob Farleys help, final draft of the script is:

declare @ltr nvarchar(1024);
SELECT @ltr = ( select 'alter table '+o.name+' drop constraint '+i.name+';'
  from sys.indexes i join sys.objects o on  i.object_id=o.object_id
  where o.type<>'S' and is_primary_key=1
  FOR xml path('') );
exec sp_executesql @ltr;

declare @qry nvarchar(1024);
select @qry = (select 'drop index '+o.name+'.'+i.name+';'
  from sys.indexes i join sys.objects o on  i.object_id=o.object_id
  where o.type<>'S' and is_primary_key<>1 and index_id>0
for xml path(''));
exec sp_executesql @qry

Answer 1

You're very close.

declare @qry nvarchar(max);
select @qry = 
(SELECT  'DROP INDEX ' + ix.name + ' ON ' + OBJECT_NAME(ID) + '; '
FROM  sysindexes ix
WHERE   ix.Name IS NOT null and ix.Name like '%prefix_%'
for xml path(''));
exec sp_executesql @qry