How to write a calculation query in SQL?

Question

Using SQL Server 2000

My Query.

SELECT 
  (Format(IIf(CLng(OutTime) > 180000, CDate('18:00:00'),  CDate(Format(OutTime, '00:00:00'))) - IIf(CLng(InTime) < 90000,  CDate('09:00:00'), CDate(Format(InTime, '00:00:00'))), 'hh:nn:ss')) As WorkTime, 
  (Format(IIf(CLng(InTime) < 90000, CDate('09:00:00') -  CDate(Format(InTime, '00:00:00')), 0) + IIf(CLng(OutTime) > 180000,  CDate(Format(OutTime, '00:00:00')) - CDate('18:00:00'), 0), 'hh:nn:ss')) As OverTime 
FROM table

Above query is Access Query, I want to write a same query in sql.

Condition.

I want to Calculate the time after 090000(HH:MM:SS) before 180000 comes in worktime, before 090000 after 180000 comes in overtime.

Intime, Outime data type is varchar in the database

Am new to SQL Server 2000

How to write a SQL query from the above same?

Answer 1

As a starter take a look at this website which shows you how to convert Access SQL statements into T-SQL as used by SQL server.

http://weblogs.sqlteam.com/jeffs/archive/2007/03/30/Quick-Access-JET-SQL-to-T-SQL-Cheatsheet.aspx

Answer 2

I don't think there's a very easy and simple way to do this - most notably because of storing time values in VARCHAR - this is really making this tricky.....

Anyway, I used an approach with two functions - one dbo.GetSeconds that converts a string representation of a time value ('103500' -> 10:35:00 hours) to a number of seconds, and then a second one dbo.GetOvertime that detects if there is any overtime.

CREATE FUNCTION dbo.GetSeconds(@input varchar(20))
RETURNS int
AS BEGIN
  DECLARE @Hour INT
  DECLARE @Minute INT
  DECLARE @Second INT

  DECLARE @TotalSeconds INT

  SET @Hour = CAST(SUBSTRING(@input, 0, LEN(@input)-3) AS INT)
  SET @Minute = CAST(LEFT(RIGHT(@input, 4), 2) AS INT) 
  SET @Second = CAST(RIGHT(@input, 2) AS INT)

  SET @TotalSeconds = @Hour * 3600 + @Minute * 60 + @Second

  RETURN @TotalSeconds
END


CREATE FUNCTION dbo.GetOvertime(@fromSeconds INT, @toSeconds INT)
RETURNS int
AS BEGIN
  DECLARE @Overtime INT

  SET @Overtime = 0

  IF @fromSeconds < 32400  -- 32400 seconds = 09:00 hours 
     SET @Overtime = @OverTime + (32400 - @fromSeconds)

  IF @toSeconds > 64800    -- 64800 seconds = 18:00 hours 
     SET @Overtime = @OverTime + (@toSeconds - 64800)

  RETURN @Overtime
END

With those two functions in place, I can fairly easily calculate what you're looking for:

SELECT
    dbo.GetOvertime(dbo.GetSeconds(InTime), dbo.GetSeconds(OutTime)) 'Overtime',
    (dbo.GetSeconds(OutTime) - dbo.GetSeconds(InTime) - 
     dbo.GetOvertime(dbo.GetSeconds(InTime), dbo.GetSeconds(OutTime))) 'Worktime',  
FROM YourTable

It's a bit involved - as I said, if you'd be on SQL Server 2008 and using the TIME data type, things would be a whole lot easier!

Marc

Answer 3

Here is literally translated query to TSQL 2000. Although, it could be rewritten for better performance:

Select Convert(char(8),
           case when DateAdd(Day,-DateDiff(Day, 0, OutTime), OutTime)>'18:00:00' 
                Then Cast('18:00:00' as datetime) 
                Else DateAdd(Day,-DateDiff(Day, 0, OutTime), OutTime) 
           End 
           - 
           Case when DateAdd(Day,-DateDiff(Day, 0, InTime),  InTime) <'09:00:00' 
                Then Cast('09:00:00' as datetime) 
                Else DateAdd(Day,-DateDiff(Day, 0, InTime),  InTime) 
           End, 
           8
          ) as WorkTime,
   Convert(char(8),
           Case when DateAdd(Day,-DateDiff(Day, 0, InTime),  InTime) <'09:00:00' 
                Then Cast('09:00:00' as datetime) - 
                     DateAdd(Day,-DateDiff(Day, 0, InTime),  InTime)
                Else Cast('00:00:00' as datetime) 
           End 
           + 
           case when DateAdd(Day,-DateDiff(Day, 0, OutTime), OutTime)>'18:00:00' 
                Then DateAdd(Day,-DateDiff(Day, 0, OutTime), OutTime) - 
                     Cast('18:00:00' as datetime) 
                Else Cast('00:00:00' as datetime) 
           End, 
           8
          ) as OverTime
From Table

Added later:

If InTime and OutTime have time part only (Date part is Jan 1 1900) you can use directly InTime and OutTime. Otherwise you have to extract time part from datetime column, as:

  DateAdd(Day,-DateDiff(Day, 0, OutTime),  OutTime)

(this is the fastest way to get time part only)

Instead of:

   DateAdd(Day,-DateDiff(Day, 0, OutTime), OutTime)>'18:00:00'

You can use

   Datepart(hh,OutTime)>17

P.S. as your time is stored as string yoiu don't need to get time part only. You can cast them to datetime, or you can write also

 cast(left(inTime,2) as int) < 9

Answer 4

You could use substring and dateadd to convert the '090000' to a real datetime field. Then you can use CASE and DATEDIFF to split work and overtime. The final formatting can be done with CONVERT. Here's an example:

select
  case when outtime-intime > '9:00:00' then '09:00:00'
    else convert(varchar(30), outtime-intime, 108)
  end as WorkTime,
  case when outtime-intime <= '9:00:00' then '00:00:00'
    else convert(varchar(30), outtime-intime-'9:00:00', 108) 
  end as OverTime
from (
  select 
    dateadd(hh,cast(substring('090000',1,2) as int),0) +
    dateadd(mi,cast(substring('090000',3,2) as int),0) +
    dateadd(ss,cast(substring('090000',5,2) as int),0) as InTime,
    dateadd(hh,cast(substring('180500',1,2) as int),0) +
    dateadd(mi,cast(substring('180500',3,2) as int),0) +
    dateadd(ss,cast(substring('180500',5,2) as int),0) as OutTime
) vw

This will print:

09:00:00  00:05:00

Answer 5

Here is code for SQL server 2000. 2005+ could do it without subquery using cross join.

Select DateAdd(mi, (Case When bef<0 Then bef else 0 end + Case When aft<0 Then aft else 0 end), diff) as WorkTome,
       DateAdd(mi, (Case When bef>0 Then bef else 0 end + Case When aft>0 Then aft else 0 end), 0)    as OverTime
From (       
Select outTime-inTime as diff,
       DateDiff(mi,t.inTime,'09:00') as bef,
       DateDiff(mi,'18:00',t.outTime) as aft
  From Table t ) as a

If Your inTime and outTime columns hase date part too, the query is slightly different:

Select DateAdd(mi, (Case When bef<0 Then bef else 0 end + Case When aft<0 Then aft else 0 end), diff) as WorkTome,
       DateAdd(mi, (Case When bef>0 Then bef else 0 end + Case When aft>0 Then aft else 0 end), 0)    as OverTime
From (       
Select outTime-inTime as diff,
       DateDiff(mi, DateAdd(Day,-DateDiff(Day, 0, t.inTime), t.inTime),'09:00') as bef,
       DateDiff(mi,'18:00',DateAdd(Day,-DateDiff(Day, 0, t.OutTime), t.OutTime)) as aft
  From #t t ) as a

Answer 6

I missed type of inTime and outTime. Here is the version for varchar

Missed that, but you just have to do Cast(inTime as datetime) . Use the first of previous 2 queries:

  Select DateAdd(mi, (Case When bef<0 Then bef else 0 end + Case When aft<0 Then aft else 0 end), diff) as WorkTome,
         DateAdd(mi, (Case When bef>0 Then bef else 0 end + Case When aft>0 Then aft else 0 end), 0)    as OverTime
  From (       
  Select Cast(t.outTime as datetime)-Cast(t.inTime as datetime) as diff,
         DateDiff(mi,Cast(t.outTime as datetime),'09:00') as bef,
         DateDiff(mi,'18:00',Cast(t.outTime as datetime)) as aft
    From Table t ) as a