adding one day to a date

Question

My code to add one day to a date returns:

date before day adding: 2009-09-30 20:24:00 date after adding one day. SHOULD be rolled over to the next month: 1970-01-01 17:33:29

<?php

    //add day to date test for month roll over

    $stop_date = date('Y-m-d H:i:s', strtotime("2009-09-30 20:24:00"));

    echo 'date before day adding: '.$stop_date; 

    $stop_date = date('Y-m-d H:i:s', strtotime('+1 day', $stop_date));

    echo ' date after adding one day. SHOULD be rolled over to the next month: '.$stop_date;
?>

Ive used pretty similar code before what am I doing wrong here?

Answer 1

I always just add 86400 (seconds in a day):

$stop_date = date('Y-m-d H:i:s', strtotime("2009-09-30 20:24:00") + 86400);

echo 'date after adding 1 day: '.$stop_date;

It's not the slickest way you could probably do it, but it works!

Answer 2

<?php
$stop_date = '2009-09-30 20:24:00';
echo 'date before day adding: ' . $stop_date; 
$stop_date = date('Y-m-d H:i:s', strtotime($stop_date . ' + 1 day'));
echo 'date after adding 1 day: ' . $stop_date;
?>

Answer 3

While I agree with Doug Hays' answer, I'll chime in here to say that the reason your code doesn't work is because strtotime() expects an INT as the 2nd argument, not a string (even one that represents a date)

If you turn on max error reporting you'll see this as a "A non well formed numeric value" error which is E_NOTICE level.