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regular expression: match any word until first space

Answer 1

+1 A:

Perhaps you could try ([^ ]+) .*, which should give you everything to the first blank in your first group.

dsolimano 2009-09-09 15:36:46

You don't need the '.*'

ire_and_curses 2009-09-09 15:41:59

Answer 2

+2 A:

([^\s]+)

works

SilentGhost 2009-09-09 15:38:16

I would further prepend ^ to get the first word only

soulmerge 2009-09-09 15:47:30

while generally correct, I think the need for `^` depends on particular language implementations or regexp. for example in Python you'd use `re.match` for this task.

SilentGhost 2009-09-09 15:51:12

Answer 3

+1 A:

This should do it:

^\S*

Jeremy Stein 2009-09-09 15:38:55

Answer 4

+1 A:

for the entire line

^(\w+)\s+(\w+)\s+(\d+(?:\/\d+){2})\s+(\w+)$

w35l3y 2009-09-09 15:43:07

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regular expression: match any word until first space

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