How do I right-align my text in Python?

Question

I have some data that I am displaying in 3 column format, of the form "key: value key: key: value key: value". Here's an example:

p: 1    sl: 10  afy: 4
q: 12   lg: 10  kla: 3
r: 0    kl: 10  klw: 3
s: 67   vw: 9   jes: 3
t: 16   uw: 9   skw: 3
u: 47   ug: 9   mjl: 3
v: 37   mj: 8   lza: 3
w: 119  fv: 8   fxg: 3
x: 16   fl: 8   aew: 3

However, I'd like if the numbers were all right aligned, such as:

a:   1
b:  12
c: 123

How can I do this in Python?

Here is the existing printing code I have:

print(str(chr(i+ord('a'))) + ": " + str(singleArray[i]) + "\t" +
    str(doubleArray[i][0]) + ": " + str(doubleArray[i][1]) + "\t" +
    str(tripleArray[i][0]) + ": " + str(tripleArray[i][1]))

Answer 1

In Python 2.5 use rjust (on strings). Also, try to get used to string formatting in python instead of just concatenating strings. Simple example for rjust and string formatting below:

width = 10
str_number = str(ord('a'))
print 'a%s' % (str_number.rjust(width))

Answer 2

If you know aa upper bound for your numbers, you can format with "%<lenght>d" % n. Given all those calculations are done and in a list of (char, num):

mapping = ((chr(i+ord('a')), singleArray[i]), 
           (doubleArray[i][0],doubleArray[i][1]), 
           (tripleArray[i][0],tripleArray[i][1])
           )
for row in mapping:
   print "%s: %3d" % row

Answer 3

Use python string formatting: '%widths' where width is an integer

>>> '%10s' % 10
'        10'
>>> '%10s' % 100000
'    100000'

Answer 4

In python 2.6+ (and it's the standard method in 3), the "preferred" method for string formatting is to use string.format() (the complete docs for which can be found here). right justification can be done with

"a string {0:5}".format(foo)

this will use 5 places, however

"a string {0:{1}}".format(foo, width)

is also valid and will use the value width as passed to .format().