<form method="POST">
<input type="checkbox" id="hrm" name="hrm" />
</form>
I mean when the form is posted.
views:
320answers:
3
A:
This how:
<?PHP
if($_POST['hrm']=='ok') echo 'checked';
else echo 'not';
?>
or:
<?PHP
if(isset($_POST['hrm'])) echo 'checked';
else echo 'not';
?>
But first you have to give value for it:
<input type="checkbox" id="hrm" name="hrm" value='ok' />
lfx
2009-09-10 06:57:12
Is value neccesary?I saw from firebug that without value it'll post something like "hrm: On".
Shore
2009-09-10 06:58:08
Watch your typos. Or `else`
random
2009-09-10 07:13:24
I'd suggest to add a value since you're otherwise depending on the user's browser to add that "On" value. I don't know if you can expect every browser to do that for you. And if a user comes along without he's screwed.
Jörg
2009-09-10 08:25:33
+2
A:
<input type="checkbox" id="hrm" name="hrm" value="yes" />
<?php
if ( isset( $_POST['hrm']) && $_POST['hrm'] === 'Yes' ) {
}
?>
meder
2009-09-10 06:58:18
+3
A:
$_GET['hrm'] or $_POST['hrm'] (depending on your form's method attribute) will be set to 'On' if it is checked, or will not be set at all if it's unchecked. In essence, you can just check using isset($_GET['hrm']) (or _POST if that's the case) - if isset() returns true, then it was checked.
Amber
2009-09-10 06:58:37