Is it possible to tell if the user of a website is using multiple monitors? I need to find the position of a popup but it's quite likely the user will have a multiple monitor setup. Whilst window.screenX etc. will give the position of the browser window it's useless for multiple monitors.
views:
748answers:
5
A:
I do not believe that it is possible right now; however js is becoming more popular for desktop use in widgets in addition to web development and that would be an excellent feature to request for a future version
Causas
2008-09-26 16:17:34
I wonder if it's something a project like Gears might implement?
slashnick
2008-09-26 16:19:52
Gears is about storing data.
Till
2008-09-26 16:22:56
+2
A:
I found this as a solution that someone has used... I do not see why you couldn't trust it.
[if the width is greater then (Height/3) * 4 > (Screen.Width) THEN]
[User has dual monitor]
[End If]
Patcouch22
2008-09-26 16:19:32
Uh... I stack my screens. Height > Width. Neither screen has the same width, so if you were hugging the max-width you would end up off-screen beyond a certain height. Not to mention two-above, one below configurations.
Shog9
2008-09-26 17:55:32
Some machines (my own) are set up as two seperate desktops so the height and width are only returned for the screen the browser is on.
slashnick
2008-09-30 12:31:28
A:
You can't do that. You could position the popup centered on the parent window however. I think it's a better idea to show a "div" as dialog in the middle of your website, because the chance that this is popup blocked is smaller and it's IMO less annoying.
Armin Ronacher
2008-09-26 16:19:34
A:
What about the size of the screen? Multiple screens have usually a great size. Just check the sizes and decide if it's reasonable to be on just one or more screens.
unexist
2008-09-26 16:19:37
+1
A:
You could make a well-educated guess with JavaScript's screen.width (.availWidth) and screen.height (.availHeight).
My idea was to assume (!) that monitors in general follow a certain ratio, whereas the .[avail]width should be outside of it because the screen is duplicated only in terms of width, but not height.
Writing this answer, it sounds like a severe hack though. Nothing I would really rely on.
Till
2008-09-26 16:22:34