tags:

views:

389

answers:

4

Hola!

If i have a string like this:

$myString = "input/name/something";

How can i get the name to be echoed? Every string looks like that except that name and something could be different.

+3  A: 

Try this:

$parts = explode('/', $myString);
echo $parts[1];

This will split your string at the slashes and return an array of the parts. Part 1 is the name.

André Hoffmann
Remember to test array items before use: if (isset($parts[1])) echo $parts[1];
drewm
+3  A: 

so the only thing you know is that :

  • it starts after input
  • it separated with forward slashes.

>

$strArray = explode('/',$myString);
$name = $strArray[1];
$something = $strArray[2];
pixeline
Great, that worked. Thanks!
A: 

use the function explode('/') to get an array of array('input', 'name', 'something'). I'm not sure if you mean you have to detect which element is the one you want, but if it's just the second of three, then use that.

Tesserex
+3  A: 

If you only need "name"

list(, $name, ) = explode('/', $myString);
echo "name is '$name'";

If you want all, then

list($input, $name, $something) = explode('/', $myString);
raspi
+1 for `list()`, it's often forgotten.
Alex Barrett