I have ABC123EFFF, I want to have 01010101010001010101.
How?
+2
A:
import binascii
binary_string = binascii.unhexlify(hex_string)
Read
Return the binary data represented by the hexadecimal string specified as the parameter.
rahul
2009-09-15 06:45:15
This returns "binary" as in the actual bytes, but it does not convert it to a printable representation as "0" and "1".
Matt Good
2009-09-15 06:52:04
http://docs.python.org/library/binascii.html is subtitled Convert between binary and ASCII. Doesn't that mean it returns a string?
pavium
2009-09-15 06:58:58
Yes, it returns a string containing the bytes represented, e.g.>>> unhexlify("ab")"\xab"
Matt Good
2009-09-15 07:03:10
+1
A:
Replace each hex digit with the corresponding 4 binary digits:
1 - 0001
2 - 0010
...
a - 1010
b - 1011
...
f - 1111
DmitryK
2009-09-15 06:46:10
Or replace each pair of hex digits with the corresponding 8 binary digits, or replace each triplet of hex digits with the corresponding 12 binary digits ... or replace each 10 hex digits, with the corresponding 40 binary digits - Oops! back where we started!
pavium
2009-09-15 06:52:49
Oh, this also omits any leading '0's so it may need padded for this use.
Matt Good
2009-09-15 07:08:49
If the input is "1a" this gives "11010", not "00011010" which may or may not be what you want.
Matt Good
2009-09-15 07:16:24
There are an infinite number of leading zeroes on every number, so I'd hope it omits them.
Glenn Maynard
2009-09-15 07:18:41
It's unfortunate that it's a global builtin. It should have been int.bin (int.oct, int.hex), instead of eating away at the global namespace.
Glenn Maynard
2009-09-15 08:16:40
It's quite reasonable to need the leading zeros (and to not need them). You might want the null byte 0x00 to be eight zero bits for example - this is important for some applications. Also the OP has a leading zero in his example (but I suspect that's just random in this case!)
Scott Griffiths
2009-09-15 09:06:11
A:
John Montgomery
2009-09-15 15:22:44
+1
A:
Another way:
import math
def hextobinary(hex_string):
s = int(hex_string, 16)
num_digits = int(math.ceil(math.log(s) / math.log(2)))
digit_lst = ['0'] * num_digits
idx = num_digits
while s > 0:
idx -= 1
if s % 2 == 1: digit_lst[idx] = '1'
s = s / 2
return ''.join(digit_lst)
print hextobinary('abc123efff')
ChristopheD
2009-09-15 19:24:01
+1
A:
hex --> decimal then decimal --> binary
#decimal to binary
def d2b(n):
bStr = ''
if n < 0: raise ValueError, "must be a positive integer"
if n == 0: return '0'
while n > 0:
bStr = str(n % 2) + bStr
n = n >> 1
return bStr
#hex to binary
def h2b(hex):
return d2b(int(hex,16))
Mat
2009-10-05 11:00:55