How to do an Integer.parseInt() for a decimal number?

Question

The Java code is as follows:

String s = "0.01";
int i = Integer.parseInt(s);

However this is throwing a NumberFormatException... What could be going wrong?

Answer 1

0.01 is not an integer (whole number), so you of course can't parse it as one. Use Double.parseDouble instead, or Float.parseFloat.

Answer 2

String s = "0.01";
double d = Double.parseDouble(s);
int i = (int) d;

The reason for the exception is that an integer isn't decimal.
A double or a float are a decimal numbers. An int not. You have to know by yourself what you need.

The way Java cast an double to a int: remove the decimal piece.

int i = (int) 0.99d;

i will by zero.

Answer 3

Use Double.parseDouble(String a) what you are looking for is not an integer as it is not a whole number.

Answer 4

Use,

String s="0.01";
int i= new Double(s).intValue();