How to set ignorecase flag for part of regular expression in Python?

Question

Is it possible to implement in Python something like this simple one:

#!/usr/bin/perl
my $a = 'Use HELLO1 code';
if($a =~ /(?i:use)\s+([A-Z0-9]+)\s+(?i:code)/){
    print "$1\n";
}

Letters of token in the middle of string are always capital. Letters of the rest of words can have any case (USE, use, Use, CODE, code, Code and so on)

Answer 1

According to the docs, this is not possible. The (?x) syntax only allows you to modify a flag for the whole expression. Therefore, you must split this into three regexp and apply them one after the other or do the "ignore case" manually: /[uU][sS][eE]...

Answer 2

As far as I could find, the python regular expression engine does not support partial ignore-case. Here is a solution using a case-insensitive regular expression, which then tests if the token is uppercase afterward.

#! /usr/bin/env python

import re

token_re = re.compile(r'use\s+([a-z0-9]+)\s+code', re.IGNORECASE)
def find_token(s):
    m = token_re.search(s)
    if m is not None:
        token = m.group(1)
        if token.isupper():
            return token

if __name__ == '__main__':
    for s in ['Use HELLO1 code',
              'USE hello1 CODE',
              'this does not match',
             ]:
        print s, '->',
        print find_token(s)

Here is the program's output:

Use HELLO1 code -> HELLO1
USE hello1 CODE -> None
this does not match -> None