One\n
Two\n
Three\n
Four\n
remove_lines(2) would remove the first two lines, leaving the string:
Three\n
Four\n
views:
342answers:
4
+6
A:
class String
def remove_lines(i)
split("\n")[i..-1].join("\n")
end
end
Calling "One\nTwo\nThree\nFour\n".remove_lines(2) would result in "Three\nFour". If you need the trailing "\n" you need to extend this method accordingly.
Koraktor
2009-09-24 06:14:08
Wouldn't the method keep empty lines as-is?
musicfreak
2009-09-24 06:16:12
Really fast ;). Checked this a minute ago. You're right.
Koraktor
2009-09-24 06:17:22
+10
A:
s.to_a[2..-1].join
>> s = "One\nTwo\nThree\nFour\n"
=> "One\nTwo\nThree\nFour\n"
>> s.to_a[2..-1].join
=> "Three\nFour\n"
DigitalRoss
2009-09-24 06:14:18
Damn. This is even better than my attempt. ;)Use `s.to_a[i..-1].join` to get the resulting `String` again.
Koraktor
2009-09-24 06:20:00
heh, I've often been frustrated in code-golf by `.to_a` doing the line break thing instead of chars like I want. FINALLY, I get a chance to use it! :-)
DigitalRoss
2009-09-24 06:25:23
Note: This will not work in Ruby 1.9, in which you'd need to do s.lines.to_a. See http://blog.grayproductions.net/articles/getting_code_ready_for_ruby_19 for more.
Greg Campbell
2009-09-24 20:53:43
+1
A:
This problem will remove the first two lines using regular expression.
Text = "One\nTwo\nThree\nFour"
Text = Text.gsub /^(?:[^\n]*\n){2}/, ''
# -----------------------------------^^ (2) Replace with nothing
# ----------------^^^^^^^^^^^^^^^^ (1) Detect first 2 lines
puts Text
EDIT: I've just saw that the question is also about 'n' lines not just two lines.
So here is my new answer.
Lines_Removed = 2
Original_Text = "One\nTwo\nThree\nFour"
Result___Text = (Original_Text.gsub(Regexp.new("([^\n]*\n){%s}" % Lines_Removed), ''))
# ^^^^^^^^^^^^^^ ^^
# - (1) Detect first lines -----++++++++++++++ ||
# - (2) Replace with nothing -----------------------------------------------------++
puts Result___Text # Returns "Three\nFour"
NawaMan
2009-09-24 06:19:21
A:
def remove_lines(str, n)
res = ""
arr = str.split("\n")[n..(str.size-n)]
arr.each { |i| res.concat(i + "\n") }
return res
end
a = "1\n2\n3\n4\n"
b = remove_lines(a, 2)
print b
Overdose
2009-09-24 06:19:55