PHP Magic Constants

Question

I am trying to get the filename of the script that is running (But not the include it is calling).

echo basename(__FILE__); # will always output include.php

echo basename($_SERVER['SCRIPT_FILENAME']);
# This will do what I want (echo myscript.php), but I was wondering if there was
# a better way to grab it, as I have had problems with $_SERVER['SCRIPT_FILENAME']
# when running certain scripts from a cron.

Any suggestions?

<?
#myscript.php
require('include.php');
echo "Hello all";
?>

<?
#include.php
echo basename(__FILE__);
echo basename($_SERVER['SCRIPT_FILENAME']);
?>

Thanks!

Answer 1

I remember using '$_SERVER["SCRIPT_NAME"]' but have no idea if it has problem with corn.

Answer 2

You have to use $_SERVER['SCRIPT_NAME'], as explained in the reserved_variables man page

'SCRIPT_NAME' Contains the current script's path. This is useful for pages which need to point to themselves. The __FILE__ constant contains the full path and filename of the current (i.e. included) file.

Answer 3

If you're using something `php -f /home/me/foo.php in your crontab (i.e. php-cli) you might also be interested in the $argv array. $argv[0] contains the path/name of the script initially passed to php.

Answer 4

When PHP is executed from the command line (likely how you have cron set up) SCRIPT_FILENAME will contain the path specified by the user. If your script is executed as ../myscript.php then that is the value you will get. Seeing as you are passing the value through basename() anyway, it should still suit your needs. What problems were you having with it exactly?

SCRIPT_NAME is another predefined variable to look at, but this will not always contain the absolute path to the executed file either.