How can I get a directory listing of resources from my Android app?

Question

My Android application has some files in the assets directory that I want to open on startup by listing the files in the directory and opening each. I am trying to use the AssetManager to do this but it does not seem to do as I would expect. My sample code is below. Is this the correct way or is there a better way to do this?

And I am using the following method to print out the assets directory tree.

void displayFiles (AssetManager mgr, String path) {
    try {
        String list[] = mgr.list(path);
        if (list != null)
            for (int i=0; i<list.length; ++i)
                {
                    Log.v("Assets:", path +"/"+ list[i]);
                    displayFiles(mgr, path + list[i]);
                }
    } catch (IOException e) {
        Log.v("List error:", "can't list" + path);
    }

}

From my Activity's onCreate method I do the following:

final AssetManager mgr = getAssets();    
displayFiles(mgr, "/assets"); 
displayFiles(mgr, "./assets"); 
displayFiles(mgr, "/");
displayFiles(mgr, "./");

Which gives me the following output

09-29 20:08:27.843: DEBUG/GFlash(6543): //AndroidManifest.xml 
09-29 20:08:27.954: DEBUG/GFlash(6543): //META-INF
09-29 20:08:28.063: DEBUG/GFlash(6543): //assets
09-29 20:08:28.233: DEBUG/GFlash(6543): //classes.dex 
09-29 20:08:28.383: DEBUG/GFlash(6543): //com
09-29 20:08:28.533: DEBUG/GFlash(6543): //res
09-29 20:08:28.683: DEBUG/GFlash(6543): //resources.arsc

Thanks in advance!

John

Answer 1

Ugh. The problem was in the displayFiles method, it was missing the separator, "/", between the directory and the filename. Sorry if I wasted anyone's time. A corrected version of displayFiles is below.

void displayFiles (AssetManager mgr, String path) {
    try {
        String list[] = mgr.list(path);
        if (list != null)
            for (int i=0; i<list.length; ++i)
                {
                    Log.v("Assets:", path +"/"+ list[i]);
                    displayFiles(mgr, path + "/" + list[i]);
                }
    } catch (IOException e) {
        Log.v("List error:", "can't list" + path);
    }

}

John