Looking for a regular expression including aplhanumeric + "&" and ";"

Answer 1

You probably want to take the problem reverse, i.e. finding all the character without the spaces:

[^ \t\n]*

Or you want to add the extra characters:

[a-zA-Z0-9&;]*

In case you want to match HTML entities, you should try something like:

(\w+|&\w+;)*

Answer 2

you should make a character class that would include the extra characters. For example:

split=re.compile('[\w&;]+')

This should do the trick. For your information

• \w (lower case 'w') matches word characters (alphanumeric)
• \W (capital W) is a negated character class (meaning it matches any non-alphanumeric character)
• * matches 0 or more times and + matches one or more times, so * will match anything (even if there are no characters there).

Answer 3

I would treat the entities as a unit (since they also can contain numerical character codes), resulting in the following regular expression:

(\w|&(#(x[0-9a-fA-F]+|[0-9]+)|[a-z]+);)+

This matches

• either a word character (including “_”), or
• an HTML entity consisting of
  • the character “&”,
    • the character “#”,
      • the character “x” followed by at least one hexadecimal digit, or
      • at least one decimal digit, or
    • at least one letter (= named entity),
  • a semicolon
• at least once.

/EDIT: Thanks to ΤΖΩΤΖΙΟΥ for pointing out an error.

Answer 4

Looks like this did the trick:

split=re.compile('(\\W+&\\W+;)*')

Thanks for the suggestions. Most of them worked fine on Reggy, but I don't quite understand why they failed with re.compile.