Is there a version of os.getcwd() that doesn't dereference symlinks?

Question

I have a Python script that I run from a symlinked directory, and I call os.getcwd() in it, expecting to get the symlinked path I ran it from. Instead it gives me the "real" path, and in this case that's not helpful. I need it to actually give me the symlinked version.

Does Python have a command for that?

Answer 1

Workaround: os.getenv('PWD')

Answer 2

In general this is not possible. os.getcwd() calls getcwd(3), and according to POSIX.1-2008 (IEEE Std 1003.1-2008):

The pathname shall contain no components that are dot or dot-dot, or are symbolic links.

os.getenv['PWD'] is shell-dependent and will not work for example with sh from FreeBSD.

Answer 3

See this question.

http://stackoverflow.com/questions/123958/how-to-get-set-logical-directory-path-in-python