Before I start coding this myself and reinventing the wheel, how do you copy a hash of hashes without duplicating the hashrefs?
I'm reading a hash of hash of hashes via Config::General. i.e., the data structure is:
my %config = ( group => { item1 => { foo => 'value',
bar => 'value',
},
item2 => { foo => 'value',
bar => 'value',
},
item3 => { foo => 'value',
bar => 'value',
},
},
);
I then pull my group from the config by dereferencing it and change the contents at runtime prior to rewriting the config file:
my %group = %{$config{'group'}};
The problem is that I need to check to see if changes were made and make associated changes to the system's file structure. I can't do this by checking:
if ($group{'item1'}{'foo'} ne $config{'group'}{'item1'}{'foo'}) {
### Stuff!
}
as $group{'item1'}
and $config{'group'}{'item1'}
are both the exact same hashref.
Now while it should be trivial to simply re-parse the config file, and compare the parsed copy from the disk against the edited version just before saving to disk, I'm sure there's a way to to a nested dereference of a complex data structure, copying the contents of the hash refs and not simply copying the references themselves. A cursory examination on CPAN doesn't turn anything up. What am I missing?
Benchmark
Got my answer:
#!/usr/bin/perl
use Benchmark qw(:all) ;
use Storable qw(dclone);
use Clone qw(clone);
my %config = ( group => { item1 => { foo => 'value',
bar => 'value',
},
item2 => { foo => 'value',
bar => 'value',
},
item3 => { foo => 'value',
bar => 'value',
},
},
);
my $ref = $config{'group'};
timethese(100000, {
'Clone' => sub { my %group = %{ clone $ref }},
'Storable' => sub { my %group = %{ dclone $ref }},
});
results in:
Benchmark: timing 100000 iterations of Clone, Storable... Clone: 2 wallclock secs ( 2.26 usr + 0.01 sys = 2.27 CPU) @ 44052.86/s (n=100000) Storable: 5 wallclock secs ( 4.71 usr + 0.02 sys = 4.73 CPU) @ 21141.65/s (n=100000)