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Answer 1

+6 A:

Since rand(n,m) returns an integer value, you should be able to do thusly:

if(rand(1,6) == $guess){
    echo "Congratulations - your guess of $guess was right!";
}
else{
    echo "No dice - better luck next time.";
}

warren 2009-10-10 01:43:18

Thanks, that really clarified how to manipulate and use rand with the if and else construct to do a comparison.

Newb 2009-10-10 04:31:55

happy it's what you were looking for :)

warren 2009-10-10 05:28:54

Answer 2

+1 A:

I'm not sure what you're trying to do. Each time this page is loaded, it will pick two random numbers, $random and $roll, and if they are equal, print them.

If you want to get the users input, you'll need to use $_POST.

$users_dice_roll = $_POST["roll"];
$random_dice_roll = rand(1,6);
if($random_dice_roll == $users_dice_roll){
    echo "You rolled: $users_guess";
}

Also, don't you need a submit button?

ABentSpoon 2009-10-10 01:56:54

Answer 3

+1 A:

I think what you're trying to do here is ask the user to input how many sides the die has and then output what the value is? The question doesn't make a lot of sense... but if the above is what you're trying to do, this should work:

choosedie.php

<h1>Choose a die number</h1>
<form method = "post" action="choosedie.php"/> 
Please choose how many sides a die should have from 1 through 6:
<br/>
<input type="text" name="roll"/>
<input type="submit" value="Submit" />
</form>

<?php
if (isset($_POST["roll"])) {
  $roll = rand(1, $_POST["roll"]);
  printf("A %s was rolled, with a maximum roll of %s", $roll, $_POST["roll"]);
}
?>

This will allow the user to input the number of sides a die has, and then print out what was rolled along with the number of sides.

sohum 2009-10-10 05:31:42

Even though the question does not make a lot of sense you where able to get what I was asking from the user, that's pretty leet.Thank you.

Newb 2009-10-11 20:05:40

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PHP choose the side a die has?

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