A couple points. You can type your return value as ViewResult if you know that's all you're going to return. Then you can interrogate that value from the overridden implementation. More importantly, according to the MVC v1 source, calling View(object) simply sets the ViewData.Model on the controller, then constructs a ViewResult.
Controller.cs:440
protected internal ViewResult View(object model) {
return View(null /* viewName */, null /* masterName */, model);
}
Controller.cs:456
protected internal virtual ViewResult View(string viewName, string masterName, object model) {
if (model != null) {
ViewData.Model = model;
}
return new ViewResult {
ViewName = viewName,
MasterName = masterName,
ViewData = ViewData,
TempData = TempData
};
}
So all you need to do is call the base method and call View(string).
namespace BaseControllers
{
public class CoolController
{
public virtual ViewResult Get()
{
var awesomeModel = new object();
return View(awesomeModel);
}
}
}
public class CoolController : BaseControllers.CoolController
{
public override ViewResult Get()
{
var ignoredResult = base.Get();
// ViewData.Model now refers to awesomeModel
return View("NotGet");
}
}
Of course you waste CPU cycles constructing the ViewResult that you ignore. So instead you can do this:
public class CoolController : BaseControllers.CoolController
{
public override ViewResult Get()
{
var baseResult = base.Get();
baseResult.ViewName = "NotGet";
return baseResult;
}
}
If your base controller returns ActionResult, you'll have to cast it to ViewResult before changing the ViewName.