What does this function do?

Question

def fun1(a):

    for i in range(len(a)):
        a[i] = a[i] * a[i]
    return a

Answer 1

It takes an array as parameter and returns the same array with each member squared.

EDIT:

Since you modified your question from 'What does this function do' to 'What is some code to execute this function', here is an example:

def fun1(a):
    for i in range(len(a)):
        a[i] = a[i] * a[i]
    return a

test1 = [1,2,3,4,5]
print 'Original list', test1
test2 = fun1(test1)
print 'Result', test2
print 'Original list', test1

The output will be:

Original list [1, 2, 3, 4, 5]
Result [1, 4, 9, 16, 25]
Original list [1, 4, 9, 16, 25]

Because the function modifies the list in place, test1 is also modified.

Answer 2

it multiplies each element of the array "a" with itself and stores the results back in the array.

Answer 3

a is passed as a list , I assume.

It squares each element of the list and returns the list.

Answer 4

It will go through your List and multiply each value by itself.

Example

a = [ 1, 2, 3, 4, 5, 6 ]

After that function a would look like this:

a = [ 1, 4, 9, 16, 25, 36 ]

Answer 5

It squares every element in the input array and returns the squared array.

So with a = [1,2,3,4,5]

result is: [1,4,9,16,25]

Answer 6

It's a trivial function that could be replaced with the one-liner:

a = [x*x for x in a]