How do I know when an interface is directly implemented in a type ignoring inherited ones?

Question

The issue appears is when I have a class implementing an interface, and extending a class which implements an interface:

class Some : SomeBase, ISome {}
class SomeBase : ISomeBase {}
interface ISome{}
interface ISomeBase{}

Since typeof(Some).GetInterfaces() returns and array with ISome and ISomeBase, i'm not able to distinguish if ISome is implemented or inherited (as ISomeBase). As MSDN I can't assume the order of the interfaces in the array, hence I'm lost. The method typeof(Some).GetInterfaceMap() does not distinguish them either.

Anyone?

Diego

Answer 1

You just need to exclude the interfaces implemented by the base type :

public static class TypeExtensions
{
    public static IEnumerable<Type> GetInterfaces(this Type type, bool includeInherited)
    {
        if (includeInherited || type.BaseType == null)
            return type.GetInterfaces();
        else
            return type.GetInterfaces().Except(type.BaseType.GetInterfaces());
    }
}

...


foreach(Type ifc in typeof(Some).GetInterfaces(false))
{
    Console.WriteLine(ifc);
}