In Python, can I print 3 lists in order by index number?

Question

So I have three lists:

['this', 'is', 'the', 'first', 'list']
[1, 2, 3, 4, 5]
[0.01, 0.2, 0.3, 0.04, 0.05]

Is there a way that would allow me to print the values in these lists in order by index?

e.g.

this, 1, 0.01 (all items at list[0])
is, 2, 0.2 (all items at list[1])
the, 3, 0.3 (all items at list[2])
first, 4, 0.04 (all items at list[3])
list, 5, 0.05 (all items at list[4])

The number of items in each list varies each time the script is run, but they always end up with the same number of values in the end. So, one time, the script could create three arrays with 30 items, another time, it could create only 15 values in each, etc.

Answer 1

Use zip

for items in zip(L1, L2, L3):
    print items

items will be a tuple with a value from each list, in order.

Answer 2

What you are probably looking for is called zip:

>>> x = ['this', 'is', 'the', 'first', 'list']
>>> y = [1, 2, 3, 4, 5]
>>> z = [0.01, 0.2, 0.3, 0.04, 0.05]
>>> zip(x,y,z)
[('this', 1, 0.01), ('is', 2, 0.20000000000000001), ('the', 3, 0.29999999999999999), ('first', 4, 0.040000000000000001), ('list', 5, 0.050000000000000003)]
>>> for (a,b,c) in zip(x,y,z):
...     print a, b, c
... 
this 1 0.01
is 2 0.2
the 3 0.3
first 4 0.04
list 5 0.05

Answer 3

lists = ( ['this', 'is', 'the', 'first', 'list'], 
          [1, 2, 3, 4, 5], 
          [0.01, 0.2, 0.3, 0.04, 0.05])
print zip(*lists)

zips the lists together and stops when the shortest list runs out of items.

Answer 4

This is the most immediately obvious way (to a python newb), and there is likely a better way, but here goes:

#Your list of lists.
uberlist = ( list1, list2, list3 )

#No sense in duplicating this definition multiple times.
#Define it up front.
uberRange = range( len( uberList ) );

#Since each will be the same length, you can use one range.
for i in range( len( list1 ) ):
    # Iterate through the sub lists.
    for j in uberRange:
        #Output
        print uberlist[ j ][ i ];