views:

1016

answers:

6

I have a long UL list I need to break up in smaller lists containing about 20 items each.

I was thinking I could use something like

$(function() {
 $("ul li:nth-child(20n)").after("</ul><ul>");
});

but that's not the case. Any idea how to use jQuery in a way that uses minimal CPU?

Thanks

+1  A: 

Nothing quite that simple (that I'm aware of at least) unfortunately. Try this as an alternative:

$(function() {
  $("ul").each(function() {
    var list = $(this);
    var size = 3;
    var current_size = 0;
    list.children().each(function() {
    console.log(current_size + ": " + $(this).text());
      if (++current_size > size) {
        var new_list = $("<ul></ul>").insertAfter(list);
        list = new_list;
        current_size = 1;
      }
      list.append(this);
    });
  });
});

You could no doubt turn this into a function that takes the chunk size as an argument but I leave that as an exercise for the reader.

cletus
+3  A: 

I would create document fragments with your removed lis and then reappend them to the location you want them. In this case, I reappended them to the body:

$(function(){
  var $bigList = $('ul#bigList'),
      group    = $bigList.find('li:lt(20)').remove();

  while(group.length){
    $('<ul/>').append(group).appendTo('body');
    group = $bigList.find('li:lt(20)').remove();
  }
});

Live Demo is at: http://jsbin.com/ejigu

Alex Sexton
A: 

Here's a working example, just change the mod 5 to mod 20.

<html>
<script type="text/javascript" src="jquery-1.3.2.js"></script>

<script type="text/javascript">

function onLoad(){
   var itemindex = 0;
   var Jlistobj = null;
   $('#list li').each(function()
   {
      if (itemindex % 5 == 0)
      {
         Jlistobj = $("<ul></ul>");
      }
      Jlistobj.append($(this));
      $('#out_div').append(Jlistobj);
      itemindex++;
   });
}

</script>
<body onLoad="onLoad()">

<ul id="list">
<li>item1</li>
<li>item2</li>
<li>item3</li>
<li>item4</li>
<li>item5</li>
<li>item6</li>
<li>item7</li>
<li>item8</li>
<li>item9</li>
<li>item10</li>
<li>item11</li>
<li>item12</li>
<li>item13</li>
<li>item14</li>
<li>item15</li>
<li>item16</li>
<li>item17</li>
<li>item18</li>
<li>item19</li>
<li>item20</li>
</ul>

<div id="out_div"></div>

</body>

</html>
Snazzer
A: 

Here is another option - I haven't profiled any of the above, so go with whatever is fastest of course. It assumes the ul in question has the id of #list.

     var listItemsPerList = 10;
     var listItems = $("ul > li").length;

     for (var i = 0; i < Math.round(listItems / listItemsPerList); i++) {
         var startingItem = i * listItemsPerList;
         var endingItem = (i + 1) * listItemsPerList;
         if (endingItem > listItems) { endingItem = listItems };
         $("ul > li").slice(startingItem, endingItem).wrapAll("<ul></ul>");
     }

     $("ul#list").replaceWith($("ul#list").children());
ScottE
A: 

you can try something like this:

$("ul").each(function(k,v)){
 split_list(v);
}

function split_list(list){
 var li_num = $(list).find("li").length;
 if(li_num > 20){
  var new_list = $("<ul></ul>");
  $(list).after(new_list);
  new_list.append($(list).find("li:gt(20)"));
  if(new_list.find("li").length > 20){
   split_list(new_list);
  }
 }
}

LE: I think it can be further refined by finding up front how many new list will be createt, create those lists and move blocks of ~20 li's into the new created lists so they will be moved only once.

jikhan
A: 

function

$.fn.splitUp=function(splitBy,wrapper){
$all= $(this).find('>*');
var fragment=Math.ceil($all.length/splitBy);

for(i=0; i< fragment; i++)
$all.slice(splitBy*i,splitBy*(i+1)).wrapAll(wrapper);
return $(this);
}

usage


$('ul#slides').splitUp(4,'<li class=splitUp><ul>')
or
$('div#slides').splitUp(3,'<div/>')

Rahen Rangan