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Question

Check if at least 75% of a string is UPPERCASE

Answer 1

+11 A:

strlen(preg_replace('/[A-Z]/', '', $str)) / strlen($str) > 0.25

Not tested, but you should get the idea.

Ignas R 2009-10-30 10:30:01

I'm thinking integer division problems here. Perhaps switching them? (original_length / changed_length) > 4?

Simon Svensson 2009-10-30 10:31:53

Awesome it works!

Time Machine 2009-10-30 10:32:36

do a check for (strlen($str) <> 0)...

egon 2009-10-30 10:33:28

Well, I presume that $str is validated for being non-empty beforehand. After all, it's an user-submitted title.

Ignas R 2009-10-30 10:36:20

And the division won't cause any problems. Even if both operands of the `/` operator are integers, the result will be a float unless they divide evenly.

Ignas R 2009-10-30 10:41:41

If you are (possibly) dealing with letters other than a-zA-Z like e.g. a danish Æ or a spanish Ñ you should take a look at the unicode support of pcre. The property \p{Lu} tests for an uper-case character. see http://www.pcre.org/pcre.txt ("UTF-8 AND UNICODE PROPERTY SUPPORT")

VolkerK 2009-10-30 11:55:01

Do you want I give credit in the source code?

Time Machine 2009-10-30 12:06:33

@Koning Baard XIV, no, of course no, thanks. It's just a small and obvious snippet of code...

Ignas R 2009-10-30 12:16:12

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Check if at least 75% of a string is UPPERCASE

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