Is is possible to print the execution time of a shell command with following combination?
root@hostname:~# "command to execute" && echo "execution time"
Is is possible to print the execution time of a shell command with following combination?
root@hostname:~# "command to execute" && echo "execution time"
root@hostname:~# time [command]
It also distinguishes between real time used and system time used.
time
is a built-in command in most shells that writes execution time information to the tty.
You could also try something like
start_time=`date +%s`
<command-to-execute>
end_time=`date +%s`
echo execution time was `expr $end_time - $start_time` s.
Or in bash
:
start_time=`date +%s`
<command-to-execute> && echo run time is $(expr `date +%s` - $start_time) s
Don't forget that there is a difference between bash's builtin time
(which should be called by default when you do time command
) and /usr/bin/time
(which should require you to call it by its full path).
The builtin time
always prints to stderr, but /usr/bin/time
will allow you to send time's output to a specific file, so you do not interfere with the executed command's stderr stream. Also, /usr/bin/time
's format is configurable on the command line or by the environment variable TIME
, whereas bash's builtin time
format is only configured by the TIMEFORMAT
environment variable.
$ time factor 1234567889234567891 # builtin
1234567889234567891: 142662263 8653780357
real 0m3.194s
user 0m1.596s
sys 0m0.004s
$ /usr/bin/time factor 1234567889234567891
1234567889234567891: 142662263 8653780357
1.54user 0.00system 0:02.69elapsed 57%CPU (0avgtext+0avgdata 0maxresident)k
0inputs+0outputs (0major+215minor)pagefaults 0swaps
$ /usr/bin/time -o timed factor 1234567889234567891 # log to file `timed`
1234567889234567891: 142662263 8653780357
$ cat timed
1.56user 0.02system 0:02.49elapsed 63%CPU (0avgtext+0avgdata 0maxresident)k
0inputs+0outputs (0major+217minor)pagefaults 0swaps