php: simulate mysql result set

Question

I'd like to pull values from textfiles in a directory and put these lists of values into arrays.

I am not sure however how to arrange these arrays into a mysql result set "like" object.

Here is what I have so far:

// Retrieve all files names, create an array
$dir    = './textfiles/';
$files1 = glob($dir . '*' . '.txt');

foreach ($files1 as $filename) 
{
    $file_array[] = basename($filename);
}

//use the file function to create arrays from the text files
$filepath = $dir . $file_array[0];
$text_array = file($filepath);

The code above only retrieves the information from 1 text file. How can I retrieve the other values into additional arrays?
Secondly once all the arrays are retrieved, how can a make the object?
Thirdly, how can I make this a function to accomodate newly created textfiles?

Answer 1

Firstly you wrote

$filepath = $dir.$file_array[0];
$text_array = file($filepath);

this piece of code only create array from the first file

You will need to loop through the array. Simply:

// Retrieve all files names, create an array
$dir    = './textfiles/';
$files1 = glob($dir . '*' . '.txt');

$arr_of_objects = array();

foreach ($files1 as $filename) 
{
    $arr = file($filename);
    $arr_of_objects[] = (object)$arr;
}

The (object) casting will help you to convert array to object.