A straightforward approach
var sorted = [{a:0,b:0},{a:2,b:1},{a:1,b:2}].sort( function( a, b )
{
if ( a.a == b.a ) return 0;
return ( a.a > b.a ) ? 1 : -1;
}).reverse();
EDIT
And a more flexible approach
// Note: console.log() require Firebug
var records = [{a:0,b:0},{a:2,b:1},{a:1,b:2}];
console.log( records );
// Sorty by 'a' ascending
sortByProperty( records, 'a' );
console.log( records );
// Sort by 'b' descending
sortByProperty( records, 'b', true );
console.log( records );
function sortByProperty( arr, property, descending )
{
arr.sort( function( a, b )
{
return Boolean( descending )
? b[property] - a[property]
: a[property] - b[property]
} );
}
EDIT 2
A version that works for strings as well
// Note: console.log() require Firebug
var records = [
{a:0,b:0}
, {a:2,b:1}
, {a:'banana',b:'apple'}
, {a:1,b:2}
, {a:'apple',b:'banana'}
];
console.log( records );
// Sorty by 'a' ascending
sortByProperty( records, 'a' );
console.log( records );
// Sort by 'b' descending
sortByProperty( records, 'b', true );
console.log( records );
function sortByProperty( arr, property, descending )
{
arr.sort( function( a, b )
{
var c = a[property].toString()
, d = b[property].toString()
if ( c == d ) return 0;
return Boolean( descending )
? d > c ? 1 : -1
: d < c ? 1 : -1
} );
}