views:

127

answers:

3

I need to port some JS code which involves Math.random()*2147483648)^(new Date).getTime(). While it looks like for smaller numbers, the python function and the JS function are equivalent in function, but with large numbers like this, the values end up entirely different.

Python:

2147483647^1257628307380

=1257075044427

Javascript:

2147483647^1257628307380

=-1350373301

How can I get the Javascript value from python?

+5  A: 

Python has unlimited-precision integers, while Javascript is using a 32-bit integer. You can manually apply a 32-bit limit to get the result you want:

def xor32bit(a, b):
    m = (a ^ b) % (2**32)
    if m > (2**16):
        m -= 2**32
    return m
Ned Batchelder
Better use `1 << 32` or directly `4294967296` instead of `2**32`.
Gumbo
Using 4294967296 would be silly—it kills readability. 2**32 is not absurdly expensive and it probably constant-folded. 1<<32 makes easily as much sense.
Mike Graham
I just checked, and Python 3.1 constant-folds `2**16` and `2**32`.
kaizer.se
Yes, it seems this was introduced in Python 2.5. 2.3 and 2.4 compute the value in bytecode, but 2.5 computes it in the compiler and the bytecode simply loads the constant value.
Ned Batchelder
+2  A: 

Easiest way would be to use ctypes to get the same overflow behavior as Javascript:

>>> import ctypes
>>> ctypes.c_int(1257075044427)
c_long(-1350373301)
truppo