Slug field followed by url

Question

Hi, I just started Django and Python, so Im still new to this.. This is my urls.py:

url(r'(?P<slug>[-\w]+)/$','person_detail'),
url(r'(?P<slug>[-\w]+)/delete/$','person_delete'),

The problem is that when I try to do to the url: slug/delete/ it's looking for that whole part slug/delete/ as the slug. When i remove the $ in the 1st url it does not go to the person_delete view, but goes to the person_detail view, ignoring the /delete/ part Any ideas?

Answer 1

Try adding a leading ^:

url(r'^(?P<slug>[-\w]+)/$','person_detail'),
url(r'^(?P<slug>[-\w]+)/delete/$','person_delete'),

That said, without the leading ^ I'd expect foo/delete/ to get you to the person_detail view with slug as delete, rather than foo/delete.

Answer 2

How about something like

url(r'(?P<slug>[^/]+)/$','person_detail'),
url(r'(?P<slug>[^/]+)/delete/$','person_delete'),

to make sure the slug can not contain a slash? You could also try having the rules in the opposite order, to try have Django match /.../delete/ first.

Answer 3

url(r'(?P<slug>[-\w]+)/delete/$','person_delete'),
url(r'(?P<slug>[-\w]+)/','person_detail'),

Url order is important in such cases, because url dispacher using first match. Common url should be last.