Regex to capture JPG images only

Question

I have this regex in PHP:

$regex = '/<img[^>]*'.'src=[\"|\'](.*)[\"|\']/Ui';

It captures all image tag sources in a string, but I want to only capture JPG files. I've tried to mess around with (.*) but I've only proven that I suck at regex... Right now I'm filtering the array but feels too much like a hack when I can just do it straight up with a proper match.

Answer 1

Just need to search for the .jpg before the closing quotes I believe

$regex = '/<img[^>]*'.'src=[\"|\'](.*\.jpg)[\"|\']/Ui';

Answer 2

you have to be careful to escape ' since you are using it as PHP delimeter.

Also searching the file which end by .jpg or jpeg would make it.

$regex = '/<img[^>]*src=["\']([^\'"]*)\.(jpg|jpeg)["\'][^>]*>/Ui';

Answer 3

Try this:

$regex = '/<img ([^>]* )?src=[\"\']([^\"\']*\.jpe?g)[\"\']/Ui';

I also removed the extra | in the character classes that was not needed.

Answer 4

Try:

$regex = '/<img[^>]*'.'src=[\"|\'](.*[.]jpg)[\"|\']/Ui';

Answer 5

You all forgot that tags may have spaces between < and img

So a correct regexp should start with /<\s*img

Answer 6

First, get all img tags with an HTML parser. Then, take those whose src attribute's value is matched by the regex \.(jpeg|jpg)$.

For example, using this parser:

$html = file_get_html('http://example.foo.org/bar.html');
foreach ($html->find('img') as $img) {
    if (preg_match ("\.(jpeg|jpg)$", $img->src) {
        //save $img or $img->src or whatever you need
    }
}

Edit: I shortened the regular expression. You can also use \.jpe?g$.