I am using xampplite1.7.2 which using PHP5.3.0 I am trying to find the file MIME type. But its giving me error:
Call to undefined function finfo_open()
I read the PHP Manual its says that this function support in PHP 5.3 and as i mention that i am using xampplite1.7.2 which using PHP5.3 then why this error occur. I also used
$_FILES['image']['type']
Which is showing me the type correctly. I am very confuse that many people i found told different ways to get MIME-TYPE by using Fileinfo and getimagesize() but none refers to $_FILES['image']['type']. What is the difference in all these functions. Actually i created doc file and then i changed it to JPG by changing its extension. My problem is that when i check the MIME type by using $_FILES['image']['type'] Its showing me image/jpeg is this showing the correct MIME_type and if i use other methods will they show me the correct type of this file which is a .doc file. Because i need to find a way to get the correct type of this file which was .doc. What are the ways to find solve this issue because i am keep trying to solve this issue sine last 24 hours but it seems very difficult to find MIME-type in PHP. i am not very exercised in working with PHP. SO please someone help me to solve this problem. Actually i want to find that the given file is a valid image file or not. Thanks