Placeholders using generic ODBC drivers

Question

Currently, I'm peppering form submissions to account for single quotes & other garbage.

 $form_field_value= str_replace("'", "''", stripslashes($form_field_value));

It is to prep the value for insertion using:

 $insert_sql = "insert into table (field) values ('".$form_field_value."')";
 odbc_exec($conn, $insert_sql);

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Essentially, I want to use placeholders for these insert/update statements.

I tried defining $par1 and $par2 as literals and then executing this

$insert_sql = "insert into table (field,txt) values (?,?)";
odbc_exec($conn, $insert_sql, $par1, $par2);

It failed and gave me this error:

Warning: odbc_exec() [function.odbc-exec]: SQL error: [Microsoft][ODBC SQL Server Driver]COUNT field incorrect or syntax error, SQL state 07001 in SQLExecDirect in test.php on line 10

Line 10 is the exec statement.

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I can't find syntax for using placeholders with this odbc driver. Any suggestions?

The $conn connection variable is working fine.

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EDIT:

Last attempt still failing - odbc_execute() is an undefined function. I have to use odbc_exec()

$par1="eggs";
$par2="milk";

$insert_crs = "insert into table (field,txt) values (?,?)";
$stmt = odbc_prepare($conn, $insert_sql); 

odbc_exec($stmt, array($par1, $par2));

Answer 1

According to http://www.php.net/manual/en/function.odbc-prepare.php , you should be preparing then executing your SQL statement, and you should be providing a new array for the third argument to dobc_execute():

<?php
$a = 1;
$b = 2;
$c = 3;
$stmt    = odbc_prepare($conn, 'CALL myproc(?,?,?)');
$success = odbc_execute($stmt, array($a, $b, $c));
?>

That means your code should look like:

$insert_sql = "insert into table (field,txt) values (?,?)";
// the following line is new, compared to your code
$stmt = odbc_prepare($conn, $insert_sql); 
// note that the following line wraps $par1 and $par2 with array()
// struck out version was incorrect - copy/paste error :(
odbc_exec($stmt, $insert_sql, array($par1, $par2));
odbc_execute($stmt, array($par1, $par2));