How do I find the length of a multi-dimensional array with reflection on java?
A:
Class clazz = Class.forName("ReflectionTest");
Method m = clazz.getDeclaredMethod("getArray");
Object o1 = m.invoke(o, arg);
int array[][] = (int[][])o1;
System.out.println("Array length: " + array.length);
System.out.println("Array length: " + array[0].length);
amischiefr
2009-11-19 16:02:56
close, but still have to know the "number" of dimensions that the array has...
Marcos Roriz
2009-11-19 16:14:33
I see what you are saying. You could create a method that can be invoked from that class that will return the number of dimensions. If you cannot modify that class, I'm not sure.
amischiefr
2009-11-19 16:23:15
Multidimensional arrays are arrays of arrays. getLength will return indeed the size of one array, but now you know the size of the containing array. Using a loop from 0 to found length – 1, you can apply getLength on each element of that first array and find out the other sizes.
dpb
2009-11-19 16:20:17
+2
A:
There is no such thing as "length" for multi-dimensional array; it may not be rectangular. I'm guessing you're talking about the number of dimensions. You need to descend into it iteratively and count.
public int getDimensionCount(Object array) {
int count = 0;
Class arrayClass = array.getClass();
while ( arrayClass.isArray() ) {
count++;
arrayClass = arrayClass.getComponentType();
}
return count;
}
ChssPly76
2009-11-19 16:25:07
+2
A:
Java arrays have lengths per instance, not all arrays in the same dimension have to have equals lengths. That said, you can get the lengths of instances in the.
Dimensions can be counted by the number of '[' in their name, this is quicker than descending the type hierarchy. The following code:
int[][][] ary = {{{0},{1}}};
Class cls = ary.getClass();
boolean isAry = cls.isArray();
String clsName = cls.getName();
System.out.println("is array=" + isAry);
System.out.println("name=" + clsName);
int nrDims = 1 + clsName.lastIndexOf('[');
System.out.println("nrDims=" + nrDims);
Object orly = ary;
for (int n = 0; n < nrDims; n++) {
int len = Array.getLength(orly);
System.out.println("dim[" + n + "]=" + len);
if (0 < len) {
orly = Array.get(orly, 0);
}
}
gives the following output:
is array=true
name=[[[I
nrDims=3
dim[0]=1
dim[1]=2
dim[2]=1
rsp
2009-11-19 17:21:57