Am stuck here!
$part_one = "abc";
$v = "one";
echo $part_???; // should output "abc"
How do I modify ??? to reference $v?
Thanks!
views:
138answers:
1
+2
A:
You need variable variables:
echo ${'part_'.$v};
// or
$var = 'part_'.$v;
echo $$var;
Gumbo
2009-11-21 08:57:19
Bingo - thanks!
RC
2009-11-21 09:00:15
Why would this ever be useful? Just curious...
Ed Swangren
2009-11-21 09:13:07
Since variable can also be used to call functions (`${'part_'.$v}()` would call the `abc` function), you can use this to compact algorithms where only the name of the function may vary. Take the `imagecreatefrom…` functions for example: Just get the image type, append it to "imagecreatefrom" and call that function: `$func = "imagecreatefrom".$type; $func($filename);`.
Gumbo
2009-11-21 10:03:20