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306

answers:

5

What is the difference between a var and val definition in Scala and why does the language need both? Why would you choose a val over a var and vice versa?

+3  A: 

val means immutable and var means mutable.

Full discussion.

Stefan Kendall
+5  A: 

val is final, that is, cannot be set. Think final in java.

Jackson Davis
But if I understand correctly (not a Scala expert), `val` *variables* are immutable, but the objects they reference don't have to be. According to the link Stefan posted: "Here names reference cannot be changed to point to a different Array, but the array itself can be modified. In other words the contents/elements of the array can be modified." So it is like how `final` works in Java.
Daniel Pryden
Exactly why I posted it as is. I can call `+=` on a mutabled hashmap defined as a `val` just fine-I believe its exactly how `final` works in java
Jackson Davis
Ack, I thought the built-in scala types could do better than simply allowing re-assignment. I need to fact-check.
Stefan Kendall
I was confusing scala's immutable Sequence types with the general notion. Functional programming has me all turned around.
Stefan Kendall
I added and removed a dummy character in your answer so I could give you the upvote.
Stefan Kendall
Why does Scala need both `val` and `var` definitions? Why have I seen few occurrences of `final` data definitions in Java? Do Java programmers simply prefer mutable over immutable variables? Is this just a bad Java programming habit?
Derek Mahar
+3  A: 

The difference is that a var can be re-assigned to whereas a val cannot. the mutability or otherwise of whatever is actually assigned assigned is a side issue:

import collection.immutable
import collection.mutable
var m = immutable.Set("London", "Paris")
m = immutable.Set("New York") //reassignment - I have change the "value" at m

Whereas:

val n = immutable.Set("London", "Paris")
n = immutable.Set("New York") //will not compile as n is a val

And hence:

val n = mutable.Set("London", "Paris")
n = mutable.Set("New York") //will not compile, even though the type of n is mutable

If you are building a data structure and all of its fields are vals, then that data structure is therefore immutable, as its state cannot change.

oxbow_lakes
That is only true if the classes of those fields are immutable as well.
Daniel
Yeah - I was going to put that in but I thought it might be a step too far! It's also an arguable point I would say; from one perspective (albeit not a functional one) its state does not change even if the state of its state does.
oxbow_lakes
+1  A: 

"val means immutable and var means mutable."

To paraphrase, "val means value and var means variable".

A distinction that happens to be extremely important in computing (because those two concepts define the very essence of what programming is all about), and that OO has managed to blur almost completely, because in OO, the only axiom is that "everything is an object". And that as a consequence, lots of programmers these days tend not to understand/appreciate/recognize, because they have been brainwashed into "thinking the OO way" exclusively. Often leading to variable/mutable objects being used like everywhere, when value/immutable objects might/would often have been better.

Erwin Smout
+10  A: 

As so many others have said, the object assigned to a val cannot be replaced, and the object assigned to a var can. However, said object can have it's internal state modified. For example:

class A(n: Int) {
  var value = n
}

class B(n: Int) {
  val value = new A(n)
}

object Test {
  def main(args: Array[String]) {
    val x = new B(5)
    x = new B(6) // doesn't work, because I can't replace the object created on the line above with this new one
    x.value = new A(6) // doesn't work, because I can't replace the object assigned to B.value for a new one
    x.value.value = 6 // works, because A.value can receive a new object
  }
}

So, even though we can't change the object assigned to x, we could change the state of that object. At the root of it, however, there was a var.

Now, immutability is a good thing for many reasons. First, if an object doesn't change internal state, you don't have to worry if some other part of your code is changing it. For example:

x = new B(0)
f(x)
if (x.value.value == 0)
  println("f didn't do anything to x")
else
  println("f did something to x")

This becomes particularly important with multithreaded systems. In a multithreaded system, the following can happen:

x = new B(1)
f(x)
if (x.value.value == 1) {
  print(x.value.value) // can be different than 1!
}

If you use val exclusively, and only use immutable data structures (ie, avoid arrays, everything in scala.collection.mutable, etc), you can rest assured this won't happen. That is, unless there's some code, perhaps even a framework, doing reflection tricks -- reflection can change "immutable" values, unfortunately.

That's one reason, but there is another reason for it. When you use var, you can be tempted into reusing the same var for multiple purposes. This has some problems:

  • It will be more difficult for people reading the code to know what is the value of a variable in a certain part of the code.
  • You may forget to re-initialize the variable in some code path, and end up passing wrong values downstream in the code.

Simply put, using val is safer and leads to more readable code.

We can, then, go the other direction. If val is that better, why have var at all? Well, some languages did take that route, but there are situations in which mutability improves performance, a lot.

For example, take an immutable Queue. When you either enqueue or dequeue things in it, you get a new Queue object. How then, would you go about processing all items in it?

I'll go through that with an example. Let's say you have a queue of digits, and you want to compose a number out of them. For example, if I have a queue with 2, 1, 3, in that order, I want to get back the number 213. Let's first solve it with a mutable.Queue:

def toNum(q: scala.collection.mutable.Queue[Int]) = {
  var num = 0
  while (!q.isEmpty) {
    num *= 10
    num += q.dequeue
  }
  num
}

This code is fast and easy to understand. Its main drawback is that the queue that is passed is modified by toNum, so you have to make a copy of it beforehand. That's the kind of object management that immutability makes you free from.

Now, let's covert it to an immutable.Queue:

def toNum(q: scala.collection.immutable.Queue[Int]) = {
  def recurse(qr: scala.collection.immutable.Queue[Int], num: Int): Int = {
    if (qr.isEmpty)
      num
    else {
      val (digit, newQ) = qr.dequeue
      recurse(newQ, num * 10 + digit)
    }
  }
  recurse(q, 0)
}

Because I can't reuse some variable to keep track of my num, like in the previous example, I need to resort to recursion. In this case, it is a tail-recursion, which has pretty good performance. But that is not always the case: sometimes there is just no good (readable, simple) tail recursion solution.

Note, however, that I can rewrite that code to use an immutable.Queue and a var at the same time! For example:

def toNum(q: scala.collection.immutable.Queue[Int]) = {
  var qr = q
  var num = 0
  while (!qr.isEmpty) {
    val (digit, newQ) = qr.dequeue
    num *= 10
    num += digit
    qr = newQ
  }
num
}

This code is still efficient, does not require recursion, and you don't need to worry whether you have to make a copy of your queue or not before calling toNum. Naturally, I avoided reusing variables for other purposes, and no code outside this function sees them, so I don't need to worry about their values changing from one line to the next -- except when I explicitly do so.

Scala opted to let the programmer do that, if the programmer deemed it to be the best solution. Other languages have choosen to make such code difficult. The price Scala (and any language with widespread mutability) pays is that the compiler doesn't have as much leeway in optimizing the code as it could otherwise. Java's answer to that is optimizing the code based on the run-time profile. We could go on and on about pros and cons to each side.

Personally, I think Scala strikes the right balance, for now. It is not perfect, by far. I think both Clojure and Haskell have very interesting notions not adopted by Scala, but Scala has its own strengths as well. We'll see what comes up on the future.

Daniel