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"contains(CharSequence s)" method in String class in JDK 1.4.2

Answer 1

+2 A:

To get the same effect as String.contains(substring) in Java 1.4, you can use the following snippet:

String.indexOf(substring) != -1

Paul Wagland 2009-11-25 09:12:42

contains() does exactly this, so no difference.

Bozho 2009-11-25 09:14:02

I have updated the answer to explain what I think the asker is asking... in particular, contains doesn't exist in Java 1.4, and that is, by my understanding of the question, where tasmohan is trying to compile.

Paul Wagland 2009-11-25 09:15:54

yes.. exactly i tried to asked what you thought.thanks for answer.

2009-11-25 10:18:10

@Paul - there is one minor nit. The `contains` method takes any `CharSequence` as an argument, but `indexOf` requires a `String` (or a `char`).

Stephen C 2009-11-25 10:57:04

@Stephen - yes, you are correct, in the case where you really want to use a 'CharSequence' you should do 'substring.toString()'.

Paul Wagland 2009-11-25 12:00:36

Updated the answer again, based on the question now clearly asking what was intended.

Paul Wagland 2009-12-02 08:39:19

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"contains(CharSequence s)" method in String class in JDK 1.4.2

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